Ph\u01b0\u01a1ng ph\u00e1p t\u00ednh l\u00f4 \u0111\u1ec1 hi\u1ec7u qu\u1ea3<\/span><\/h2>\nPh\u01b0\u01a1ng ph\u00e1p 1: Xu\u1ea5t hi\u1ec7n 3 s\u1ed1 gi\u1ed1ng nhau trong 1 gi\u1ea3i k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1<\/span><\/h3>\nKhi xu\u1ea5t hi\u1ec7n 3 s\u1ed1 gi\u1ed1ng nhau trong 1 gi\u1ea3i x\u1ed5 s\u1ed1 th\u00ec c\u00e1c b\u1ea1n lo\u1ea1i b\u1ecf 3 s\u1ed1 gi\u1ed1ng nhau \u0111\u00f3 \u0111i, c\u00f2n l\u1ea1i s\u1ed1 n\u00e0o th\u00ec l\u1ea5y s\u1ed1 to nh\u1ea5t gh\u00e9p v\u1edbi con s\u1ed1 b\u00e9 nh\u1ea5t kh\u00e1c 0 c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t \u0111\u00e1nh l\u00f4 trong 3 ng\u00e0y ti\u1ebfp theo.<\/p>\n
L\u01b0u \u00fd:\u00a0Ph\u01b0\u01a1ng ph\u00e1p n\u00e0y ch\u1ec9 \u00e1p d\u1ee5ng cho k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 t\u1eeb gi\u1ea3i 1 \u0111\u1ebfn gi\u1ea3i 6, kh\u00f4ng l\u1ea5y k\u1ebft qu\u1ea3 c\u1ee7a gi\u1ea3i 7.<\/p>\n
V\u00ed d\u1ee5:<\/p>\n
Ng\u00e0y 30\/9 k\u1ebft qu\u1ea3 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u1ec1 92603 th\u00ec l\u1ea5y s\u1ed1 nh\u1ecf nh\u1ea5t kh\u00e1c 0 l\u00e0 s\u1ed1 3<\/p>\n
Gi\u1ea3i 5 s\u1ed1 c\u00f3 33356 l\u1ea5y s\u1ed1 l\u1edbn nh\u1ea5t l\u00e0 s\u1ed1 6<\/p>\n
Gi\u1ea3i 4 s\u1ed1 c\u00f3 33348 l\u1ea5y s\u1ed1 l\u1edbn nh\u1ea5t l\u00e0 s\u1ed1 8<\/p>\n
Gi\u1ea3i 3 s\u1ed1 c\u00f3 333 th\u00ec l\u1ea5y s\u1ed1 0<\/p>\n
Ta gh\u00e9p c\u00e1c c\u1eb7p s\u1ed1 l\u1ea1i v\u00e0 \u0111\u00e1nh l\u00f4 trong 3 ng\u00e0y li\u00ean ti\u1ebfp. M\u1ed9t\u00a0c\u00e1ch ch\u01a1i l\u00f4 \u0111\u1ec1\u00a0r\u1ea5t hay v\u00e0 hi\u1ec7u qu\u1ea3 \u0111\u01b0\u1ee3c r\u1ea5t nhi\u1ec1u \u00e1p d\u1ee5ng th\u00e0nh c\u00f4ng.<\/p>\n
Ph\u01b0\u01a1ng ph\u00e1p 2: L\u1ea5y s\u1ed1 tr\u00f9ng \u0111\u1ea7u v\u00e0 tr\u00fang \u0111\u00edt<\/span><\/h3>\nCh\u1ecdn c\u00e1c s\u1ed1 \u1edf gi\u1ea3i 6 v\u00e0 gi\u1ea3i 7 c\u1ee7a k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1. Trong c\u00e1c gi\u1ea3i \u0111\u00f3, gi\u1ea3i n\u00e0o tr\u00f9ng \u0111\u1ea7u th\u00ec l\u1ea5y 2 s\u1ed1 \u0111\u1ea7u c\u1ee7a 2 gi\u1ea3i \u1edf gi\u1eefa \u0111\u1ec3 gh\u00e9p l\u1ea1i th\u00e0nh c\u1eb7p \u0111\u00e1nh l\u00f4 trong 3 ng\u00e0y li\u00ean ti\u1ebfp.<\/p>\n
T\u01b0\u01a1ng t\u1ef1, gi\u1ea3i n\u00e0o tr\u00f9ng \u0111\u00edt (tr\u00fang 2 s\u1ed1 cu\u1ed1i) th\u00ec l\u1ea5y 2 s\u1ed1 cu\u1ed1i c\u1ee7a 2 gi\u1ea3i \u1edf gi\u1eefa \u0111\u1ec3 gh\u00e9p l\u1ea1i th\u00e0nh c\u1eb7p \u0111\u00e1nh l\u00f4 trong 3 ng\u00e0y.<\/p>\n
Ph\u01b0\u01a1ng ph\u00e1p 3: D\u00f9ng 3 s\u1ed1 li\u1ec1n nhau tr\u00f9ng \u0111\u1ea7u<\/span><\/h3>\nX\u00e9t c\u00e1c gi\u1ea3i x\u1ed5 s\u1ed1, n\u1ebfu trong 1 gi\u1ea3i m\u00e0 xu\u1ea5t hi\u1ec7n 3 s\u1ed1 li\u1ec1n nhau v\u00e0 tr\u00f9ng \u0111\u1ea7u th\u00ec trong 3 ng\u00e0y ti\u1ebfp theo 3 con l\u00f4 \u1ea5y s\u1ebd kh\u00f4ng xu\u1ea5t hi\u1ec7n n\u1eefa m\u00e0 ch\u00fang ta s\u1ebd ch\u1ecdn l\u1ea5y 2 trong 3 con l\u00f4 \u0111\u00f3 \u0111\u1ec3 nu\u00f4i.<\/p>\n
V\u00ed d\u1ee5:\u00a0Ng\u00e0y 2\/10 v\u1ec1 3 con l\u00f4 li\u00ean ti\u1ebfp tr\u00f9ng \u0111\u00e2u: 22, 23, 24<\/p>\n
3 ng\u00e0y ti\u1ebfp theo 3\/10, 4\/10, 5\/10 s\u1ebd kh\u00f4ng v\u1ec1 m\u00e0 m\u00ecnh s\u1ebd ch\u1ecdn 2 trong 3 con l\u00f4 \u0111\u1ec3 nu\u00f4i trong 3 ng\u00e0y ti\u1ebfp theo n\u1eefa l\u00e0 6\/10, 7\/10, 8\/10.<\/p>\n
Ph\u01b0\u01a1ng ph\u00e1p 4: Nu\u00f4i l\u00f4 2 ng\u00e0y<\/span><\/h3>\n\u1ede ph\u01b0\u01a1ng ph\u00e1p n\u00e0y s\u1ebd x\u00e9t c\u00e1c s\u1ed1 trong gi\u1ea3i 4. N\u1ebfu c\u00f3 d\u1ea1ng 2 s\u1ed1 gi\u1eefa \u0111\u01b0\u1ee3c k\u1eb9p b\u1edfi m\u1ed9t s\u1ed1 ho\u1eb7c k\u1eb9p v\u1edbi b\u00f3ng c\u1ee7a n\u00f3 th\u00ec ta l\u1ea5y 2 s\u1ed1 gi\u1eefa \u0111\u1ec3 \u0111\u00e1nh l\u00f4 cho 3 ng\u00e0y ti\u1ebfp theo.<\/p>\n
Ph\u01b0\u01a1ng ph\u00e1p 5: Nu\u00f4i gi\u1ea3i \u0111\u1eb7c bi\u1ec7t<\/span><\/h3>\nPh\u01b0\u01a1ng ph\u00e1p n\u00e0y r\u1ea5t \u0111\u01a1n gi\u1ea3n, ng\u01b0\u1eddi ch\u01a1i ch\u1ec9 c\u1ea7n c\u1ed9ng c\u00e1c con s\u1ed1 trong gi\u1ea3i \u0111\u1eb7c bi\u1ec7t gh\u00e9p v\u1edbi con s\u1ed1 0 ho\u1eb7c s\u1ed1 8 \u0111\u1ec3 l\u1ea5y c\u1eb7p v\u00e0 nu\u00f4i trong 3 ng\u00e0y ti\u1ebfp theo.<\/p>\n
V\u00ed d\u1ee5:\u00a0Gi\u1ea3i \u0111\u1eb7c bi\u1ec7t ng\u00e0y 1\/10 v\u1ec1 587463<\/p>\n
C\u00f4ng c\u00e1c s\u1ed1 l\u1ea1i ta c\u00f3 5+8+7+4+6+3=33, 3+3=6<\/p>\n
Gh\u00e9p s\u1ed1 6 v\u1edbi s\u1ed1 0 ho\u1eb7c s\u1ed1 8 ta c\u00f3 c\u00e1c c\u1eb7p s\u1ed1 060, 686<\/p>\n<\/div>\n<\/article>\n
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soi c\u1ea7u si\u00eau vip<\/h4>\n
Khi xu\u1ea5t hi\u1ec7n 3 s\u1ed1 gi\u1ed1ng nhau trong 1 gi\u1ea3i x\u1ed5 s\u1ed1 th\u00ec c\u00e1c b\u1ea1n lo\u1ea1i b\u1ecf 3 s\u1ed1 gi\u1ed1ng nhau \u0111\u00f3 \u0111i, c\u00f2n l\u1ea1i s\u1ed1 n\u00e0o th\u00ec l\u1ea5y s\u1ed1 to nh\u1ea5t gh\u00e9p v\u1edbi con s\u1ed1 b\u00e9 nh\u1ea5t kh\u00e1c 0 c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t \u0111\u00e1nh l\u00f4 trong 3 ng\u00e0y ti\u1ebfp theo.<\/p>\n
L\u01b0u \u00fd:\u00a0Ph\u01b0\u01a1ng ph\u00e1p n\u00e0y ch\u1ec9 \u00e1p d\u1ee5ng cho k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 t\u1eeb gi\u1ea3i 1 \u0111\u1ebfn gi\u1ea3i 6, kh\u00f4ng l\u1ea5y k\u1ebft qu\u1ea3 c\u1ee7a gi\u1ea3i 7.<\/p>\n
V\u00ed d\u1ee5:<\/p>\n
Ng\u00e0y 30\/9 k\u1ebft qu\u1ea3 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u1ec1 92603 th\u00ec l\u1ea5y s\u1ed1 nh\u1ecf nh\u1ea5t kh\u00e1c 0 l\u00e0 s\u1ed1 3<\/p>\n
Gi\u1ea3i 5 s\u1ed1 c\u00f3 33356 l\u1ea5y s\u1ed1 l\u1edbn nh\u1ea5t l\u00e0 s\u1ed1 6<\/p>\n
Gi\u1ea3i 4 s\u1ed1 c\u00f3 33348 l\u1ea5y s\u1ed1 l\u1edbn nh\u1ea5t l\u00e0 s\u1ed1 8<\/p>\n
Gi\u1ea3i 3 s\u1ed1 c\u00f3 333 th\u00ec l\u1ea5y s\u1ed1 0<\/p>\n
Ta gh\u00e9p c\u00e1c c\u1eb7p s\u1ed1 l\u1ea1i v\u00e0 \u0111\u00e1nh l\u00f4 trong 3 ng\u00e0y li\u00ean ti\u1ebfp. M\u1ed9t\u00a0c\u00e1ch ch\u01a1i l\u00f4 \u0111\u1ec1\u00a0r\u1ea5t hay v\u00e0 hi\u1ec7u qu\u1ea3 \u0111\u01b0\u1ee3c r\u1ea5t nhi\u1ec1u \u00e1p d\u1ee5ng th\u00e0nh c\u00f4ng.<\/p>\n
Ph\u01b0\u01a1ng ph\u00e1p 2: L\u1ea5y s\u1ed1 tr\u00f9ng \u0111\u1ea7u v\u00e0 tr\u00fang \u0111\u00edt<\/span><\/h3>\nCh\u1ecdn c\u00e1c s\u1ed1 \u1edf gi\u1ea3i 6 v\u00e0 gi\u1ea3i 7 c\u1ee7a k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1. Trong c\u00e1c gi\u1ea3i \u0111\u00f3, gi\u1ea3i n\u00e0o tr\u00f9ng \u0111\u1ea7u th\u00ec l\u1ea5y 2 s\u1ed1 \u0111\u1ea7u c\u1ee7a 2 gi\u1ea3i \u1edf gi\u1eefa \u0111\u1ec3 gh\u00e9p l\u1ea1i th\u00e0nh c\u1eb7p \u0111\u00e1nh l\u00f4 trong 3 ng\u00e0y li\u00ean ti\u1ebfp.<\/p>\n
T\u01b0\u01a1ng t\u1ef1, gi\u1ea3i n\u00e0o tr\u00f9ng \u0111\u00edt (tr\u00fang 2 s\u1ed1 cu\u1ed1i) th\u00ec l\u1ea5y 2 s\u1ed1 cu\u1ed1i c\u1ee7a 2 gi\u1ea3i \u1edf gi\u1eefa \u0111\u1ec3 gh\u00e9p l\u1ea1i th\u00e0nh c\u1eb7p \u0111\u00e1nh l\u00f4 trong 3 ng\u00e0y.<\/p>\n
Ph\u01b0\u01a1ng ph\u00e1p 3: D\u00f9ng 3 s\u1ed1 li\u1ec1n nhau tr\u00f9ng \u0111\u1ea7u<\/span><\/h3>\nX\u00e9t c\u00e1c gi\u1ea3i x\u1ed5 s\u1ed1, n\u1ebfu trong 1 gi\u1ea3i m\u00e0 xu\u1ea5t hi\u1ec7n 3 s\u1ed1 li\u1ec1n nhau v\u00e0 tr\u00f9ng \u0111\u1ea7u th\u00ec trong 3 ng\u00e0y ti\u1ebfp theo 3 con l\u00f4 \u1ea5y s\u1ebd kh\u00f4ng xu\u1ea5t hi\u1ec7n n\u1eefa m\u00e0 ch\u00fang ta s\u1ebd ch\u1ecdn l\u1ea5y 2 trong 3 con l\u00f4 \u0111\u00f3 \u0111\u1ec3 nu\u00f4i.<\/p>\n
V\u00ed d\u1ee5:\u00a0Ng\u00e0y 2\/10 v\u1ec1 3 con l\u00f4 li\u00ean ti\u1ebfp tr\u00f9ng \u0111\u00e2u: 22, 23, 24<\/p>\n
3 ng\u00e0y ti\u1ebfp theo 3\/10, 4\/10, 5\/10 s\u1ebd kh\u00f4ng v\u1ec1 m\u00e0 m\u00ecnh s\u1ebd ch\u1ecdn 2 trong 3 con l\u00f4 \u0111\u1ec3 nu\u00f4i trong 3 ng\u00e0y ti\u1ebfp theo n\u1eefa l\u00e0 6\/10, 7\/10, 8\/10.<\/p>\n
Ph\u01b0\u01a1ng ph\u00e1p 4: Nu\u00f4i l\u00f4 2 ng\u00e0y<\/span><\/h3>\n\u1ede ph\u01b0\u01a1ng ph\u00e1p n\u00e0y s\u1ebd x\u00e9t c\u00e1c s\u1ed1 trong gi\u1ea3i 4. N\u1ebfu c\u00f3 d\u1ea1ng 2 s\u1ed1 gi\u1eefa \u0111\u01b0\u1ee3c k\u1eb9p b\u1edfi m\u1ed9t s\u1ed1 ho\u1eb7c k\u1eb9p v\u1edbi b\u00f3ng c\u1ee7a n\u00f3 th\u00ec ta l\u1ea5y 2 s\u1ed1 gi\u1eefa \u0111\u1ec3 \u0111\u00e1nh l\u00f4 cho 3 ng\u00e0y ti\u1ebfp theo.<\/p>\n
Ph\u01b0\u01a1ng ph\u00e1p 5: Nu\u00f4i gi\u1ea3i \u0111\u1eb7c bi\u1ec7t<\/span><\/h3>\nPh\u01b0\u01a1ng ph\u00e1p n\u00e0y r\u1ea5t \u0111\u01a1n gi\u1ea3n, ng\u01b0\u1eddi ch\u01a1i ch\u1ec9 c\u1ea7n c\u1ed9ng c\u00e1c con s\u1ed1 trong gi\u1ea3i \u0111\u1eb7c bi\u1ec7t gh\u00e9p v\u1edbi con s\u1ed1 0 ho\u1eb7c s\u1ed1 8 \u0111\u1ec3 l\u1ea5y c\u1eb7p v\u00e0 nu\u00f4i trong 3 ng\u00e0y ti\u1ebfp theo.<\/p>\n
V\u00ed d\u1ee5:\u00a0Gi\u1ea3i \u0111\u1eb7c bi\u1ec7t ng\u00e0y 1\/10 v\u1ec1 587463<\/p>\n
C\u00f4ng c\u00e1c s\u1ed1 l\u1ea1i ta c\u00f3 5+8+7+4+6+3=33, 3+3=6<\/p>\n
Gh\u00e9p s\u1ed1 6 v\u1edbi s\u1ed1 0 ho\u1eb7c s\u1ed1 8 ta c\u00f3 c\u00e1c c\u1eb7p s\u1ed1 060, 686<\/p>\n<\/div>\n<\/article>\n
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soi c\u1ea7u si\u00eau vip<\/h4>\n
X\u00e9t c\u00e1c gi\u1ea3i x\u1ed5 s\u1ed1, n\u1ebfu trong 1 gi\u1ea3i m\u00e0 xu\u1ea5t hi\u1ec7n 3 s\u1ed1 li\u1ec1n nhau v\u00e0 tr\u00f9ng \u0111\u1ea7u th\u00ec trong 3 ng\u00e0y ti\u1ebfp theo 3 con l\u00f4 \u1ea5y s\u1ebd kh\u00f4ng xu\u1ea5t hi\u1ec7n n\u1eefa m\u00e0 ch\u00fang ta s\u1ebd ch\u1ecdn l\u1ea5y 2 trong 3 con l\u00f4 \u0111\u00f3 \u0111\u1ec3 nu\u00f4i.<\/p>\n
V\u00ed d\u1ee5:\u00a0Ng\u00e0y 2\/10 v\u1ec1 3 con l\u00f4 li\u00ean ti\u1ebfp tr\u00f9ng \u0111\u00e2u: 22, 23, 24<\/p>\n
3 ng\u00e0y ti\u1ebfp theo 3\/10, 4\/10, 5\/10 s\u1ebd kh\u00f4ng v\u1ec1 m\u00e0 m\u00ecnh s\u1ebd ch\u1ecdn 2 trong 3 con l\u00f4 \u0111\u1ec3 nu\u00f4i trong 3 ng\u00e0y ti\u1ebfp theo n\u1eefa l\u00e0 6\/10, 7\/10, 8\/10.<\/p>\n
Ph\u01b0\u01a1ng ph\u00e1p 4: Nu\u00f4i l\u00f4 2 ng\u00e0y<\/span><\/h3>\n\u1ede ph\u01b0\u01a1ng ph\u00e1p n\u00e0y s\u1ebd x\u00e9t c\u00e1c s\u1ed1 trong gi\u1ea3i 4. N\u1ebfu c\u00f3 d\u1ea1ng 2 s\u1ed1 gi\u1eefa \u0111\u01b0\u1ee3c k\u1eb9p b\u1edfi m\u1ed9t s\u1ed1 ho\u1eb7c k\u1eb9p v\u1edbi b\u00f3ng c\u1ee7a n\u00f3 th\u00ec ta l\u1ea5y 2 s\u1ed1 gi\u1eefa \u0111\u1ec3 \u0111\u00e1nh l\u00f4 cho 3 ng\u00e0y ti\u1ebfp theo.<\/p>\n
Ph\u01b0\u01a1ng ph\u00e1p 5: Nu\u00f4i gi\u1ea3i \u0111\u1eb7c bi\u1ec7t<\/span><\/h3>\nPh\u01b0\u01a1ng ph\u00e1p n\u00e0y r\u1ea5t \u0111\u01a1n gi\u1ea3n, ng\u01b0\u1eddi ch\u01a1i ch\u1ec9 c\u1ea7n c\u1ed9ng c\u00e1c con s\u1ed1 trong gi\u1ea3i \u0111\u1eb7c bi\u1ec7t gh\u00e9p v\u1edbi con s\u1ed1 0 ho\u1eb7c s\u1ed1 8 \u0111\u1ec3 l\u1ea5y c\u1eb7p v\u00e0 nu\u00f4i trong 3 ng\u00e0y ti\u1ebfp theo.<\/p>\n
V\u00ed d\u1ee5:\u00a0Gi\u1ea3i \u0111\u1eb7c bi\u1ec7t ng\u00e0y 1\/10 v\u1ec1 587463<\/p>\n
C\u00f4ng c\u00e1c s\u1ed1 l\u1ea1i ta c\u00f3 5+8+7+4+6+3=33, 3+3=6<\/p>\n
Gh\u00e9p s\u1ed1 6 v\u1edbi s\u1ed1 0 ho\u1eb7c s\u1ed1 8 ta c\u00f3 c\u00e1c c\u1eb7p s\u1ed1 060, 686<\/p>\n<\/div>\n<\/article>\n
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soi c\u1ea7u si\u00eau vip<\/h4>\n
Ph\u01b0\u01a1ng ph\u00e1p n\u00e0y r\u1ea5t \u0111\u01a1n gi\u1ea3n, ng\u01b0\u1eddi ch\u01a1i ch\u1ec9 c\u1ea7n c\u1ed9ng c\u00e1c con s\u1ed1 trong gi\u1ea3i \u0111\u1eb7c bi\u1ec7t gh\u00e9p v\u1edbi con s\u1ed1 0 ho\u1eb7c s\u1ed1 8 \u0111\u1ec3 l\u1ea5y c\u1eb7p v\u00e0 nu\u00f4i trong 3 ng\u00e0y ti\u1ebfp theo.<\/p>\n
V\u00ed d\u1ee5:\u00a0Gi\u1ea3i \u0111\u1eb7c bi\u1ec7t ng\u00e0y 1\/10 v\u1ec1 587463<\/p>\n
C\u00f4ng c\u00e1c s\u1ed1 l\u1ea1i ta c\u00f3 5+8+7+4+6+3=33, 3+3=6<\/p>\n
Gh\u00e9p s\u1ed1 6 v\u1edbi s\u1ed1 0 ho\u1eb7c s\u1ed1 8 ta c\u00f3 c\u00e1c c\u1eb7p s\u1ed1 060, 686<\/p>\n<\/div>\n<\/article>\n
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